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Casting from f64 to u64 does not work #1867
Description
Fix error when converting between two different types
for example:
x:i16 = i16(3)
y:u16 = x
Converting i16 to u16.
{{ message }}
Fix error when converting between two different types
for example:
x:i16 = i16(3)
y:u16 = x
Converting i16 to u16.
Activity
Smit-create commentedon May 29, 2023
You need to explicitly define the cast. The following should work fine:
certik commentedon May 29, 2023
Thanks @Smit-create, indeed the code you posted works for me in both LLVM and C backends:
@ronnuriel can you please try it out and let us know if that fixes it for you?
ronnuriel commentedon Jun 4, 2023
The following works:
cycles_count: i64
end_cycle: i64 = i64(100)
start_cycle: i64 = i64(4)
num_iters: i64 = i64(4)
but when u64 its not:
cycles_count: u64 #THIS LINE
end_cycle: i64 = i64(100)
start_cycle: i64 = i64(4)
num_iters: i64 = i64(4)
ERROR:
|
181 | cycles_count = u64((end_cycle - start_cycle) / num_iters)
| ^^^^^^^^^^^^ ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ type mismatch ('u64' and 'f64')
certik commentedon Jun 4, 2023
I see, casting from f64 to u64 does not work. I think that's a bug, thanks for reporting it. As a workaround until this gets fixed, this worked for me:
[-]converting between different types - C backend [/-][+]Casting from f64 to u64 does not work[/+]Darshan4852 commentedon Jun 9, 2023
x: i16 = i16(3)
y: u16
if x >= 0:
y = u16(x)
else:
y = u16(2 ** 16 - 1)
I hope it will work.